Need Help with command

[Mike_305]

Hello,

Trying to sort the files under "/dev" and running the following command and it's not working. What am I doing incorrect.

ll /dev/*/group | awk '(printf $6 "\n")' | sort -n

I am doing this to find out what is the next number I can use for mknod command.

Thanks in advance!


MP

[James R. Ferguson · Accepted solution]

Hi:

# ls -l /dev/*/group | awk '{printf "%s\n", $6}' | sort -n

Regards!

...JRF...

[TTr]

ll /dev/*/group | sort -k6,6

The -k option of sort is very powerful. Character or numeric sorting covers the hex nature of the minor number

If you want to be more specific

ll /dev/*/group | sort -k6.3,6.4

[Mike_305]

Hello,

Thanks for the quick reply. Both of you guys are de "MAN".

It is always help having the right syntax in the command.

This one gives me what I was looking for and it's easy to determine which next "HEX" number I can use for my MKNOD.

Appreciate your help.

THX - MP

[Dennis Handly]

>ll /dev/*/group | awk '(printf $6 "\n")' | sort -n

Instead of using awk's printf, you could just use: print $6
You could also print the filename.

[Mike_305]

Hello Dennis,

I had the same command line and the option that you suggested does not work.

Thanks for your help.

Thanks,

MP

[Mike_305]

Hello,

thanks for your help. The only command works is James and TTr's.

Thanks for your help.

Thanks,

MP

[Dennis Handly]

>I had the same command line and the option that you suggested does not work.

Sorry, I was copying your line and just suggesting you not use printf. I didn't notice you had () vs {}.
So here would be my suggestion combining the JRF and my filename solutions:
ll /dev/*/group | awk '{print $6,$10}' | sort