if [ $Num = [0 OR 1 OR 2] ]; then echo " Num is > 0 but < 3 " else if [ $Num = 3 OR 4] and $Char='Y' ];then echo " num < 5 and char is : 'Y' else echo " num > 5 and char is : 'N' fi; fi;
Can some one please help me to right correctly these conditions.
if [ $Num -ge 0 -a $Num -lt 3 ] ; then echo " Num is > 0 but < 3 " elif [ $Num -eq 3 -o $Num -eq 4 ] ; then if [[ $Char = 'Y' ]] ; then echo " num < 5 and char is : 'Y'" fi elif [[ $Char = 'N' ]] ; then echo " num > 5 and char is : 'N'" else echo " num > 5 and char is : 'Y' " fi
I think this would be easier solved by using Case statement instead of if's. But I'm guessing you have a plan for this so here we go :).
if [ $Num -ge 0 -a $Num -lt 3 ]; then echo "Num is > 0 but < 3" else if [ $Num -ge 3 -a $Num -le 4 ]; then if [ "$Char" == "Y" ]; then echo " num < 5 and char is : 'Y'" else echo " num < 5 and char is : 'N'" fi elif [ $Num -ge 5 ]; then if [ "$Char" == "Y" ]; then echo " num > 5 and char is : 'Y'" else echo " num > 5 and char is : 'N'" fi fi fi
I made som modifications to yours since it didn't account for all the possible versions. And I added a elif :)
I do not see any benefit in putting everything in one line, except for code being a bit long. Infact u should have the 2 conditions separate so as to also check for Char = N even if Num=3 or 4.
if [ $Num -eq 0 -o $Num -eq 1 -o $Num -eq 2 ]; then echo " Num is > 0 but < 3 " else if [ $Num -eq 3 -o $Num -eq 4 ]&[ "$Char" = "Y" ];then echo " num < 5 and char is : 'Y'" else echo " num > 5 and char is : 'N'" fi fi
-------------------------------------------- # OR Num=10 Char='Y'
if [ $Num -eq 0 -o $Num -eq 1 -o $Num -eq 2 ]; then echo " Num is > 0 but < 3 " elif [ $Num -eq 3 -o $Num -eq 4 ]&[ "$Char" = "Y" ];then echo " num < 5 and char is : 'Y'" else echo " num > 5 and char is : 'N'" fi
OK Rules of the test for shell script: Comparison operator ------------------- - Numeric: -eq -ne -lt -le -gt -ge - String: = !=
Logical operator ---------------- Numeric: ! Not -a And -o Or String: ! Not && And || Or
OK, - If you want to make two numeric comparision with and if [ Cond1 -a Cond2 ];then # Here Cond like $a -lt 5
- If you want to make and with or if [ Cond1 -a Cond2 -o Cond3 ];then
- But you want to change the order of testing if [ Cond1 -s \( Cond2 -a Cond3 \) ];then #Here spaces are important
- You want to compare two strings with and or or
if [ Cond1 ]&&[ Cond2 ]||[Cond3 ];then
Similarly you want to compare integer comparision with string with and
if [ intCond ]&&[ stringCond ];then
I hope now you will be able to do all possible comarisions.
That should be "&&": elif [ $Num -eq 3 -o $Num -eq 4 ] && [ "$Char" = "Y" ]; then Or using arithmetic expressions: elif (( Num == 3 && Num == 4 )) && [ "$Char" = "Y" ]; then
>You want to compare two strings with and or or if [ Cond1 ]&&[ Cond2 ]||[Cond3 ]; then
There is no need to use multiple test operators, you can use -a or -o
