Print in awk

[M. Tariq Ayub]

Hi,

I want to print the last colum using awk. the column number may very

drwxrwxr-x 2 tariq users 1024 Jun 27 13:36 .
drwxr-xr-x 5 tariq users 1024 Jun 27 12:11 ..
-rw-rw-r-- 1 tariq users 5 Jun 27 13:36 test
w-rw-r-- 1 tariq users 6 Jun 10 09:38 file01
-rw-rw-r-- 1 tariq users 7 Jun 10 09:38 file02
-rw-rw-r-- 1 tariq users 7 Jun 10 09:39 file03

from the above putput i want to print only
test
file01
file02
file03

How can i do that. I cannot use print $4 as sometime the file name will be in different column.

[Con O'Kelly]

Hi

Sorry if I'm misunderstanding you, but can you not use:
$ ls -l | awk '{print $9}' | grep -v "^.[?]"

OR alternatively use:
$ ls -l | awk '{print $NF}' | grep -v "^.[?]"

Cheers
Con

[Muthukumar_5]

You can get last column with NF parameter as,

ls -l | awk '{ print $NF }'

hth.

[Cem Tugrul]

Hi,
another solution but similiar as others
from me;
ls -lrt|grep -v "^d"|awk '{print $NF}'
Good Luck,

[Cem Tugrul]

"^d" anchor directory so "grep -v exclude
directories so you can get only files...
good luck,

[Peter Nikitka]

Hi,

if you really want to list files only, try

ls -p | awk '!/[@/]'

It's fast and you need not bother with filenames containing spaces.

mfG Peter

[Muthukumar_5]

You can also try with perl as,


# ls -l | perl -ne 'split(/ /); $var=@_; $var-=1;print $_[$var];'

hth.

[Brian Butscher]

If all you want to do is print the file names, why not use "ls |lp -dprintername"? No need to use awk.

Regards,

Brian

[Sandman!]

Why use awk or sed when you can do it simply with the ls command:

# ls -1

cheers!