Report number of open files per process

[Florin_6]

Hello,

The number of open files in my system is pretty high and I do not understand why.
I would like to get a report with all processes and the total number of opened files for each process. Like this I can see in the top of the list the processes that are having the higher number of opened files.

I used glance to check the total number of opened files and to see the processes that take most of the CPU time. However the process having most of CPU does not necessarily has the highest number of files open. So glance is not solving my problem.... unless there is a screen/option I did not discover.

Probably a better option would be to use lsof but I could not manage to make it work the way I want it.

Thanks for any hint you can give me!
Florin

[Christian Gebhardt]

Hi

you can use lsof to list open files of a process

http://hpux.asknet.de/hppd/hpux/Sysadmin/lsof-4.64/

Chris

[John Poff]

Hi Florin,

As you mentioned, the lsof utility is the best tool for what you need. Here is a recent thread about the question of matching the nfile parameter in the kernel to the number of open files reported by lsof:

http://forums.itrc.hp.com/cm/QuestionAnswer/1,,0x973f28c64656d71190080090279cd0f9,00.html

JP

[U.SivaKumar_2]

Hi,

Why not...

Here iam finding out the number of open files by httpd process.

#lsof | grep httpd | grep -vi listen | wc -l
192

regards,

U.SivaKumar

[steven Burgess_2]

Hi Florin

yes lsof is the best tool as mentioned. For open files per single process within glance look at -F option

glance -F
enter PID (3476)

HTH

Steve

[Ramkumar Devanathan · Accepted solution]

Florin,

this would help to get the number of files open per process with lsof's output -

lsof | awk '{procct[$1]++;procname[$1]=$1;}END{for (i in procname) {printf ("%s, %d\n",procname[i],procct[i]);}}'

- ramd.

[Christian Gebhardt]

Hi

Here's a script to better use lsof

lsof | awk '{line[NR]=$1}
END {
count=0
for (i=2 ; i <=NR ; i++)
{
if (line[i] != line [i-1])
{printf("%s %s\n",count, line[i-1])
count=1}
else
{count++
}
}
}' | sort -n


Chris