Retrieving password expiering date

[Klaas D. Eenkhoorn]

All,

How can i retrieve the password expiering date of a users password.
I'm using a non trusted system and no NIS.

I was testing with the output of passwd -a -s but what i thought to be a date (the 11/27/03 part) "bz99999 PS 11/27/03 0 7" seems to be something else.
I've started testing on 27 November 2003 :`-)

Can someone help me ?
I want to be 1 step ahead of the regular password changing sceme of login and rlogin.

Klaas Eenkhoorn

[Jean-Louis Phelix]

Hi,

logins -a should do it.

Regards.

[Klaas D. Eenkhoorn]

But how do i interpert this info ?

"bz99999 3101 group 105 Test login,,, -1 000000"

Where is the date ?

Kl@@S

[Jean-Louis Phelix · Accepted solution]

Hi,

Sorry, but I made a mistake. You should rather use -x :

exemple :

foo:O74257ZI2iaLA,M.UP:....

This user has M.UP as password aging string.

M means 24 weeks (168 days) before expiration
. means 0
UP is the last change date

Login -x -l foo gives for the last line :

PS 092503 0 168 -1

PS --> valid password
092503 --> last pasword change (derived from UP)
168 --> numbers of days between passord changes (derived from M).

So change will occur a last on september 15 2003 + 168 days ...

Regards.

[Klaas D. Eenkhoorn]

Ok, it's starting to come to me . . . or getting further away . . .

The output of passwd -a is "bz99999 PS 11/27/03 0 7".
A non trusted system calculates it's dates in weeks and it's weeks start on Theursday.
This means that login or rlogin will allways ask for a new password on Theursday ???

If a password is valid for example 14 day's (two whole weeks) and if i change this password on 2 December 2003 the date recorded in the passwd file will be 27 November 2003. (the first previous Theursday)
And the date the password expieres will be 11 December 2003 ???

Am i right ??

Klaas

[Jean-Louis Phelix]

Klass,

I agree ... Your passwd aging field begin with something like ',0.' for this user (see man 4 passwd)

Regards.