rows for which the last letter ends

[ram kumar_4]

Please help me out

I want a unix shell script command to do the following:
- Read this x1.txt and create 3 separate files a.dat, b.dat and
c.dat
- a.dat should have all the rows for which the last letter ends
with
"A"
- b.dat should have all the rows for which the last letter ends
with
"D"
- c.dat should have all the rows for which the last letter ends
with
"C"

Thanks

[Simon Hargrave · Accepted solution]

grep "A$" x1.txt > a.dat
grep "D$" x1.txt > b.dat
grep "C$" x1.txt > c.dat

The $ in the expression matches end of line and is anchored to your letter.

[Hein van den Heuvel]

The simple multiple greps should do.
But if somehow (pipe!) you can only go over the data once, then you coudl use perl or awk like so:


awk 'BEGIN {f["A"]="a.dat";f["D"]="b.dat";f["C"]="c.dat"} {print $0 >> f[substr($0,length($0))]}' all.dat


Hein.

[Muthukumar_5]

We can identify the pattern on a file which occurs on the input file with $

Example:


x1.txt
------

power script eA
bye for now
Test enviginee yeB
ncie choke C
test byeD
over


grep 'A$' x1.txt > a.dat
grep 'D$' x1.txt > b.dat
grep 'C$' x1.txt > c.dat

You can get multiple patterns as,

grep 'A$|B$' x1.txt > ab.txt

HTH.
+Muthu+