Script help

[Prashant Zanwar_4]

I want to write a script which will tell me number of sessions open by users on a system. and I want to know top ten of them?
How to acheive this..

Thanks
Prashant

[RAC_1 · Accepted solution]

for i in 'logins -u|awk '{print $1}'`
do
count=`who -u|grep ${i} | awk '{print $1}'|wc -l`
user=`who -u|grep ${i} | awk '{print $1}'|uniq`

echo "${count} ${user}" >> /tmp/user-list
sort -rnk1 /tmp/user-list|head -10
done

Anil

[H.Merijn Brand (procura]

# whodo

is also a nice - lesser known - command

Enjoy, Have FUN! H.Merijn [ who'd do it in perl with Proc::ProcessTable ]

[Prashant Zanwar_4]

Any way to acheive using perl..just curious.

Thanks a lot.

Prashant

[Prashant Zanwar_4]

Can someone please reply if this can be acheived using perl..

perl experts!

Thanks
Prashant

[H.Merijn Brand (procura]

Example of may (daily used) perl replacement for ps attached

Enjoy, Have FUN! H.Merijn