Script help

[Nobody's Hero]

Ok, Im stuck here. Im not a great script creator.
After I run this script I wrote that looks for directoris with lots of files, I end up with this listing. ist column being the number of files in that die, the second column being the directory name:
3088 /zones/s1dfa89/root/usr/share/man/man3mlib
how can I read the file and just pull out the lines that are over 3000?

[Jeff_Traigle · Accepted solution]

awk '{if ($1 > 3000) print}' datafile

[Nobody's Hero]

Thanks, Im a stupe sometimes:

[Robert-Jan Goossens]

grep 3[0-9][0-9][0-9] file

Robert-Jan

[Hein van den Heuvel]

And for the lazy, or poorly typing, folks:

awk '$1>3000' your-file



0 points for this please.

Cheers,
Hein.

[Peter Nikitka]

Hi,

... and if you just need the filename(s) for further processing:
awk '$1>3000 {print $2}' listing-file

mfG Peter