Script Required

[M.sureshkumar]

Hi All,
We need script for % of cpu and free memory.
1.sar -uM 1 1
vvc1app2@root>sar -uM 2 2
HP-UX vvc1app2 B.11.11 U 9000/800 09/08/06

12:02:56 cpu %usr %sys %wio %idle
12:03:01 0 0 0 0 100
1 1 0 0 99
2 0 1 0 99
3 11 1 0 89
system 3 1 0 97
12:03:21 0 0 0 0 100
1 0 0 0 100
2 0 0 0 100
3 0 0 1 99
system 0 0 0 100

Average 0 1 1 1 98
Average 1 3 1 0 97
Average 2 0 1 1 98
Average 3 5 1 0 93
Average system 2 1 0 97

2.app2@root>vmstat
procs memory page faults cpu
r b w avm free re at pi po fr de sr in sy cs us sy id
1 0 0 188372 3379377 107 16 0 0 0 0 0 1057 1540 139 0 1 99

Requirement:
1.In sar -uM 5 5 command output ,the last line gives the aveage % idle for cpu i.e 97%.If we will subtract from 100%,it will give % of CPU used i.e 3%(100 -97 =3%).We need this output i.e % of CPU used, in single script .
2.In vmstat command ouput,the free memory is 3379377 KB.If we will multiply by 4, it will give free memory in KB,after that we will divide by 1024 it will give in MB and again divide by 1024 it will give in GB.We need out put in GB only in single script.

The above two requirement is required in single script.Pls give the script for the above requirement.

Regards,
Suresh.

[RAC_1 · Accepted solution]

sar -uM 1 4|grep 'Average system' | awk '{printf "%d %s\n",(100-$NF),"%"}'
vmstat 1 4|awk '{print $5}'|grep -v '[a-zA-Z]'|awk '{(s+=$1)} END {printf "%d %s\n",s*4096/1024,MB}'

Down and dirty though.

[Peter Nikitka]

Hi,

a modified/simplified version (note for printf:
%% -> %):

sar -uM 1 4 | awk '/Average system/ {printf("%d%%s\n",100-$NF)}'

vmstat | awk '/^ *[0-9]/ {printf("%dGB\n",$5/256/1024)}'

mfG Peter

[M.sureshkumar]

Hi All,

Thank you for ur given input.

Regards,
Suresh.