script to sequence log files

[Vin_5]

Hi,

I'm trying to simplify a script I have for sequencing files, maybe someone has one already or advice on the best way to go about it?

The script applies sequence numbers to log files each day from 001->100.

File names are of the format .log, so I want to change them to 001.log up to 100.log, and then start again at 001 by running the script each day.

Any help much appreciated,

Vin.

[Massimo Bianchi]

Try something like this (no hpux on hands)


COUNT=1

while $COUNT < 101
do
DATE=$( date +%a%I )
touch /dir/$COUNT$DATE.log
let COUNT=COUNT+1
done



HTH,
Massimo

[James R. Ferguson]

Hi:

Assuming that your files were named like '20030612_hhmmss' something like this would do:

#!/usr/bin/sh
typeset -i N
typeset D=`date +%Y%m%d`
cd /tmp
for F in `ls f${D}*.log`
do
(( N=N+1 ))
mv ${F} ${N}${F}
done
exit 0

Regards!

...JRF...

[Jean-Louis Phelix]

Hi,

first of all I would create 100 empty files (001.log to 100.log). then it would be easy to run the script every day :

#!/usr/bin/sh
I=1
while [ $I -le 100 ]
do
touch $(printf "%3.3d.log" $I)
I=$((I+1))
sleep 1
done

without sleep, it seems that files could have creation time in the wrong order. It's run only once, so ...

Then, you can run this script every day. Argument should be the new log file, or you can directly get it from the script using a ls pattern or a date :

#!/usr/bin/sh
TARGET=$(ls -rt [01][0-9]*.log | line)
mv $1 $(echo $TARGET | cut -c1-3)_$1
rm $TARGET

Regards.

[Martin Robinson]

A useful hint is the typeset command in ksh. Use 'typeset -Z3 name' to make sure the variable 'name' is always printed with 3 digits, leading zeros.

ie:
typeset -Z3 name
a=1
echo $a
001

This will simplify the filenaming side of things.