scripting question

[Charles McCary]

Group,

Anyway to add two decimal numbers of differing precision in a ksh script?

tx,

C

[James R. Ferguson · Accepted solution]

Hi Charles:

Try this:

echo "1.11 + 3.3"|bc

...JRF...

[Abel Berger]

For example :

set typ -i x
x=`echo 100.99 + 200.88 | bc`
echo $x

[Abel Berger]

For example :

set type -i x
x=`echo 100.99 + 200.88 | bc`
echo $x

[Johannes Falk]

Oops,
set type -i x
is nonsense! This sets $1 to "type", $2 to "-i" and $3 to "x"

But a typeset -i x
would set $x to integer, and this is not usefull here, because the
result is a float.

So simply use:
$ x=$(echo "1.11+3.3"|bc); echo "$x"
4.41
is ok

By the way, mind the precision in bc:
$ echo 'scale=6; 10/3' | bc
3.333333
$ echo 'scale=3; 10/3' | bc
3.333
$ echo '10/3' | bc
3

Hanno

[Abel Berger]

Hi Falk,

I MADE THE TEST AND ITS FUNCTIONED.
I WOULD LIKE THAT YOU MADE TOO.
THEREFORE WHEN YOU USE BC COMMAND THE
INTEGER VARIABLE BECOMES FLOATING,

OK.

[Johannes Falk]

Hi Abel,

I didn't understand your last question but I tested this:
c13:/tmp$ x=$(echo "1.11+3.3"|bc); echo "$x"
4.41
c13:/tmp$ typeset -i x
c13:/tmp$ x=$(echo "1.11+3.3"|bc); echo "$x"
4

So x remains an int if it is set so,
and the result becomes truncated.

[Abel Berger]

Hi Falk,

The problem among my test and your test is
the ` `. Your test use () and $ therefore the
results are different.
Test makes equal mine is above and looks at the result. OK !

Regards...
Abel Berger