Scripting Question

[Craig Rants]

I have to breakdown the contents of a field in the same manner each time I come upon this field. The format of the field is 123456789XX0000. I want to remove the first 9 numbers from the field so the result would be XX0000. I know how I would approach this for command line arguments with shift. And I know how I could do this by processing each field through a while or for statment. But this is quite a big file and I don't want this to run all weekend. So basically my question is, is there a way to format the field in a similar manner to the shift command.

All responses are appreciated.

Craig

[James R. Ferguson · Accepted solution]

Hi Craig:

Try this:

# echo "123456789xxxx1234"|awk '{print substr($0,10,8)}'

Regards!

...JRF...

[Craig Rants]

Bingo!
Good to see the master at work.

Craig

[Deshpande Prashant]

HI
One more choise if you need fields from 10th position through last.

echo "1234567890xabcdef" |cut -c 10-

Thanks.
Prashant.

[Darrell Allen]

Hi Craig,

Here's another way:

echo "123456789xxxx1234"|cut -c10-

Darrell

[Craig Rants]

I had tried cut and I must have missed something in my syntax.

Now I know.

Craig

[harry d brown jr]

echo "123456789XX0000"|sed "s/^\([0-9]\{9\}\)\(.*\)/\2/"

for xx0000

or echo "123456789XX0000"|sed "s/^\([0-9]\{9\}\)\(..\)\(.*\)/\3/"

for 0000

live free or die
harry