scripting question

[Smucker]

I need to be able to take on the command line of a command and later spit it back out. The problem is there are quotes whitespaces that need to be handled....

example

xxxxx.sh -a -o param -h -n "title name" filename

any ideas

[Steven E. Protter]

Shalom,

scripting 101

spaced arguments are automatically put in variables, in the order on the command line left to right.

scriptname parm1 parm2 parm3

echo $1
# shows parm1

etc

SEP

[Bill Hassell]

Scripting 102...the entire command line parameter list can be seen with $@ so you can write your script like this:

MYPARMS="$@"

and later:

echo "parms= $ABC"

Note the prolific use of " marks. The quote marks will preserve embedded spaces. Now asa Steven mentioned, the parameters will be separated with white space so if you put extra spaces (or tabs) between values on the line, they will not be preserverd, but the spaces inside a parameter enclosed with quote marks will be preserved.

[James R. Ferguson]

Hi:

# cat ./seeargs
#!/usr/bin/sh
echo "----------"
for X in "$@"
do
echo $X
done
echo "----------"

# ./seeargs -a -o param -h -n "title name" filename
----------
-a
-o
param
-h
-n
title name
filename
----------

Regards!

...JRF...

[Tingli]

Again, you can use either quote or escape to do the job.

xxxxx.sh -a -o param -h -n \"title name\" filename

xxxxx.sh -a -o param -h -n '"title name"' filename