Shell script help needed.

[sunil_34]

Hi,

my requirement, I have multiple files .Now i want to read each line of each file.; and do the following grep in each line one after another.
grep -h 'APPLNAME= MAESTRO=' $LINE
grep -h 'ls:BEGIN' $LINE
grep -h 'ds:END' $LINE
end.

how can i do that.

Can anyone help...

regards,
Sunil.

[Mark Grant]

Sunil,

I think you are more specific about your requirements, we might be able to do what you want without ging through line by line and doing a grep. That way is really slow.

Let us know what you really want:)

[sunil_34]

the requirement is that a diractory has say 12 files which are log files of different days. i ant to find the grep arguments
from the files line by line and save it in a file in that order. In short i want to
record the application name and start and end time from the log files to a different
file.

[Sanjay Kumar Suri]

Is this what you need?

for i in `ls`
do
grep -h "search string" $i
done

sks

[sunil_34]

Sanjay,

the ls argument gives me file wise i want line wise .i.e line by line for say four diff. files

[Sanjay Kumar Suri]

Check this

for i in `ls`
do
for j in `cat $i`
do
grep -h "search string" $j
done
done

sks

[Manish Srivastava]

Hi,

you could do this:

for i in `ls`
do
while read line
do
grep "pattern"
some more operation
done < $i
done

Hope this fits your requirement.

manish

[Robert A. Pierce]

Sunil,

If by $LINE you mean each line of each file, then you could change $LINE to FILE_PATTERN (e.g., 2004_Jun*.log), and change this:

grep -h 'APPLNAME= MAESTRO=' $LINE
grep -h 'ls:BEGIN' $LINE
grep -h 'ds:END' $LINE

to this:

grep -h -e 'APPLNAME= MAESTRO=' -e 'ls:BEGIN' -e 'ds:END' FILE_PATTERN

Does that help?