shell script

[vas bolpali]

Hi guys,

the output of "df -k" is giving the following output.
/home (/dev/vg02/lvol2 ) : 17364312 total allocated Kb
2772080 free allocated Kb
14592232 used allocated Kb
84 % allocation used
/usr (/dev/vg00/lvol7 ) : 1471160 total allocated Kb
1034935 free allocated Kb
436225 used allocated Kb
29 % allocation used



I want as followes.
/home /usr
84 % 29 %


can some body suggest the shell script?
the script must use 'df' command ( not 'bdf').
Thnx in advance.
VB

[John Palmer]

Hi,

Try the following but you may have to adjust the printf statements to cater for the maximum length filesystem name that you have (I have allowed only 10 chars...

#!/usr/bin/sh

let NUM=0

df -k | {
while read A B C
do
if [[ ${A} = /*(?) ]];
then MP[NUM]=${A}
continue
fi

if [[ ${B} = % ]];
then PCT[NUM]=${A}
let NUM=NUM+1
continue
fi
done
}

let TOTAL=NUM

let NUM=0
while ((NUM < TOTAL));
do
printf "%10s" ${MP[NUM]}
let NUM=NUM+1
done

print

let NUM=0
while ((NUM < TOTAL));
do
printf "%9s\%" ${PCT[NUM]}
let NUM=NUM+1
done

print

exit

Regards,
John

[John Dvorchak · Accepted solution]

#!/bin/ksh
echo "/home /usr"
HOM=`df -k /home|grep %|awk '{print $1}'`
USR=`df -k /usr |grep %|awk '{print $1}'`
echo "$HOM % $USR %"

Sorry my first example was for /var and /usr. But now you can compare them both and see that there isn't much to make if work for any filesystem or any number of file systems.

[John Dvorchak]

#!/bin/ksh
echo "/var /usr"
VAR=`df -k /var|grep %|awk '{print $1}'`
USR=`df -k /usr |grep %|awk '{print $1}'`
echo "$VAR % $USR %"


This should work for you.

[Kellogg Unix Team]

How about using the following -

bdf /home /usr

...Manjeet