simple: for i in 1 2 3 4 -----> 2000

[Bill McNAMARA_1]

loop until value less than 2000

best way!

addition:
if i % 16 is 0 (but not for i=0) echo "/n"

Thanks,
Bill

[Deepak Extross]

Bill,
for the loop, whats wrong with this:
i=0;
while [ $i -lt 2000 ]
do
echo $i
i=`expr $i + 1`
done

[Mary Ann Lipa]

where can I start learning that kinda language?...

Thanks Bill..
d_b

[Robin Wakefield]

Hi Bill,

#!/bin/ksh
i=0
while [ $i -le 2000 ] ; do
echo $i '\c'
if [ `expr $i % 16` -eq 0 ] && [ $i -ne 0 ] ; then
echo
fi
i=`expr $i + 1`
done

Rgds, Robin.

[Deepak Extross · Accepted solution]

this one has the mod-16 bit in cluded:

i=0;
p=0;
while [ $i -lt 100 ]
do
echo $i
i=`expr $i + 1`
p=`expr $p + 1`
if [ $p -eq 16 ]
then
echo "\n"
p=0
fi
done

does this help?

[Deepak Extross]

coming from someone crowned almost 4 times, is this some kind of trick question?

[Karvendhan M]

how is it?

# /usr/bin/perl
for (1 .. 2000) {
print <<`EOF`
echo $_
EOF
}

or....

for i in `perl -e 'for (1 .. 2000) { print "$_\n" }'`
do
echo $i
done



~ Karvendhan M.

[Bill McNAMARA_1]

Thanks Deepak,

I ask because I've gotten _*real*_ lazy with the forums here!
I only got crowned once btw.. 4 wizard caps nearly! ;)

Later,
Bill

[Frank Slootweg]

Re:

i=`expr $i + 1`

If you have a Korn or POSIX shell script, then it is much more effective to use:

((i=$i+1))

The '((...))' construct is executed by the shell, while expr(1) is an external command, i.e. one process per iteration of the loop.

For the empty loop (2000 times), the time on my system went from 22 seconds to 0.2 seconds.

[Craig Rants]

Bill,
Frank deserves a 10 for his contribution. I tested it and he was right on. I am going to change all my scripts to use that construct where applicable.

Kudos to Frank,
C

[David Lodge]

My example:

typeset -Z4 i=1
while (( i < 2000 ))
do
print -n $i
(( i % 16 == 0 ))&& print
(( i += 1 ))
done

(the typeset is to neatly round make all numbers 4 digits)

I don't really think I could get it smaller without resorting to awk:
awk 'BEGIN {for (i=1;i<2000;i++) { printf "%s ",i; if (i % 16 == 0) print "" } }'

dave