Simple question for sed/awk/perl experts

[Yogeeraj_1]

Hello,

I am not a very good script programmer :(

Please help!

The following file should be modified:

...
/backup01/pfs/sy/frm/sy001oc0.fmb
/backup01/pfs/sy/frm/rf910oc0.fmb
/backup01/pfs/sy/frm/rf920oc0.fmb
/backup01/pfs/sy/frm/rf930oc0.fmb
/backup01/pfs/sy/frm/rf940oc0.fmb
/backup01/pfs/sy/frm/rf950oc0.fmb
/backup01/pfs/sy/frm/rf001oc0.fmb
/backup01/pfs/sy/frm/rf810oc0.fmb
...

to become:

...
f60gen /backup01/pfs/sy/frm/sy001oc0.fmb ops\$yd/yd@pfs Compile_All=YES
f60gen /backup01/pfs/sy/frm/rf910oc0.fmb ops\$yd/yd@pfs Compile_All=YES
f60gen /backup01/pfs/sy/frm/rf920oc0.fmb ops\$yd/yd@pfs Compile_All=YES
f60gen /backup01/pfs/sy/frm/rf930oc0.fmb ops\$yd/yd@pfs Compile_All=YES
f60gen /backup01/pfs/sy/frm/rf940oc0.fmb ops\$yd/yd@pfs Compile_All=YES
f60gen /backup01/pfs/sy/frm/rf950oc0.fmb ops\$yd/yd@pfs Compile_All=YES
f60gen /backup01/pfs/sy/frm/rf001oc0.fmb ops\$yd/yd@pfs Compile_All=YES
f60gen /backup01/pfs/sy/frm/rf810oc0.fmb ops\$yd/yd@pfs Compile_All=YES
...

I have tried "sed" in my script:

cat myfile.log | sed s/\/backup01/f60gen \/backup01 > f1.log
cat f1.log | sed s/.fmb/.fmb ops\$yd/yd@pfs Compile_All=YES > myfile.log


and am getting the following error:

sed: Function s//backup01/f60gen cannot be parsed.
sed: Function s/.fmb/.fmb cannot be parsed.


Thanks a lot for a solution or any simple alternatives.

Best Regards
Yogeeraj

[H.Merijn Brand (procura]

# perl -ple 's{(.*)}{f60gen $1 ops\\$yd/yd\@pfs\nCompile_All=YES}

not tested

[H.Merijn Brand (procura]

add missing trailing quote yourself :)

[Christian Gebhardt · Accepted solution]

Hi
awk '{printf("f60gen %s ops\$yd/yd@pfs Compile_All=YES \n",$0)}' inputfile

Chris

[Pete Randall]

Yogeeraj,

You're very close - you just need a trailing / in your sed command:

cat myfile.log | sed s/\/backup01/f60gen \/backup01/ > f1.log

(the trailing / is between "backup01" and "> f1.log"

Same thing in the second case.

I think that should do it.

Pete

[H.Merijn Brand (procura]

and replace the \n with a space. The forum wrapped your example, and, since I don't know f60gen, I presumed these on a new line. Reading the awk solution showed me you meant it to be the last argument

[Yogeeraj_1]

hi all,

Chris: Wonderful it works! Thanks.


procura: or should i call you "perl" master? ;) Thanks a lot. Although i gave a hard task of "add missing trailing quote".

It was as if i was asking you a tip on the phone :)

Problem solved. period.


Best Regards
Yogeeraj

[Yogeeraj_1]

hi again

pete:
Encouraging reply. however does not work :(.

still giving me error:

sed: Function s//backup01/f60gen cannot be parsed.

Procura:
I am a bit lost! where do i specify my file as argument?

Thanks a lot
Yogeeraj

[Christian Gebhardt]

Hi

sed Version

sed -e 's/\/backup01/f60gen \/backup01/' -e 's/fmb/fmb ops$yd\/yd@pfs Compile_All=YES/' infile
Chris

[H.Merijn Brand (procura]

# perl -ple 's{(.*)}{f60gen $1 ops\\$yd/yd\@pfs Compile_All=YES} ' filename

or

# perl -ple 's{(.*)}{f60gen $1 ops\\$yd/yd\@pfs Compile_All=YES} ' < filename

or

# script_to_generate_list |
# perl -ple 's{(.*)}{f60gen $1 ops\\$yd/yd\@pfs Compile_All=YES} '

[Yogeeraj_1]

thank chris.

that was great!

Everything is working fine here!

Cheers
Yogeeraj

[Yogeeraj_1]

hi all,

with all your helps, my fully working script now looks as follows:
============================================================
#!/bin/sh
DIR=/backup01/pfs

find ${DIR} -xdev -type f -name '*.fmb'|sed -e 's/\/backup01/f60gen \/backup01/' -e 's/fmb/fmb ops$yd\/yd@pfs Compile_All=YES/' > compile_all.sh
find ${DIR} -xdev -type f -name '*.mmb'|sed -e 's/\/backup01/f60gen \/backup01/' -e 's/mmb/mmb ops$yd\/yd@pfs Compile_All=YES module_type=menu/' >> compile_all.sh
find ${DIR} -xdev -type f -name '*.pll'|sed -e 's/\/backup01/f60gen \/backup01/' -e 's/pll/pll ops$yd\/yd@pfs Compile_All=YES module_type=library/' >> compile_all.sh
#end-YD
============================================================

thank you forum!

Cheers
Yogeeraj