some grepping and seding

[Amit Dixit_2]

Hi
I have a directory list like this
CD_1.0
REL_3.0

I want a command through which I can just
extract the numerical part if i replace
SUFFIX BEFORE "_"

Thanks
Amit

[RAC_1]

Is numerical part always after _ ??

awk -F "_" '{print $2}'

Anil

[Bharat Katkar]

Hi Amit,
Is what you are looking for:
# pwd
/abc
# ll
total 0
drwxrwxrwx 2 root sys 96 Aug 9 17:50 CD_1.0
drwxrwxrwx 2 root sys 96 Aug 9 17:52 REL_3.0
# ll | cut -d "_" -f2
total 0
1.0
3.0
#
Regards,

[Steve Steel]

Hi

echo $value|cut -f2 -d"_"


Steve Steel

[Amit Dixit_2]

Hi Bharat,

How to get rid of total and and how to
assign this value to a variable.

Thanks
Amit

[Massimo Bianchi]

Hi,
what about:

VALUE=$( ls | cut -d "_" -f2 )

echo $VALUE


HTH,
Massimo

[Kent Ostby]

As Massimo points out, you can assign a value for any of these commands as:

VALUE=$()

To clarify the awk command that someone listed above, you'd need:

ll | awk -F "_" '{print $2}'

or

VALUE=$( ll | awk -F "_" '{print $2}')

Best regards,

Kent M. Ostby

[Bharat Katkar]

Amit,
See if this works for you.

#!/usr/bin/ksh
list=`ls | cut -d "_" -f 2`
funct1 $list
funct1()
{
V1=$#
x=1
while true
do
if [ $V1 -gt 0 ]
then
VAR$x=$1
shift
let x=x+1
let V1=V1-1
else
exit
fi
done
}

Hope that helps.
Regards,

[Muthukumar_5]

We can do it with awk programming easily as,

# ls
CD_1.0 REL_3.0 test_4.0
# ls | awk -F _ '{ s += $2 } END { print "sum = " s }'
sum = 8


It will give the value. You can assign to a new variable and can be used in operation following this.

And one more ,

your profile says as,
http://forums1.itrc.hp.com/service/forums/publicProfile.do?userId=CA1059455&forumId=1

I have assigned points to 78 of 400 responses to my questions.

It is good to take time to resolve this :)