Something like grep

[Ed Hon]

In a script, I have a third party command that produces three lines of output. I need to "grep" the third line but don't want to specifiy a pattern. How do I do that? TIA.

[Stephane Vinsot]

just

| tail -1

it will display the last line

[John Palmer]

One way is to use a combination of 'head' and 'tail'. To get the third line from a file:-

head -n 3 | tail -n 1

Regards,
John

[Victor BERRIDGE]

tail -n1
e.g.
vi gaga
werthvkjhmrlgvhlmrmv
weitvjmhmrev
wethmlrhg
"gaga" [New file] 3 lines, 44 characters
alphard:/home/logadm # tail -n1 gaga
wethmlrhg
alphard:/home/logadm #

[Alan Riggs]

Just to be different:

| sed -n 3p

[Rick Garland]

I use the sed -n 3p

Can also do sed -n 1-3p to print the lines 1-3

[Stephane Vinsot]

Just to be ridiculous ;)

| (read line ; read line ; read line ; echo $line)

yes, it prints the 3rd line...

[Alan Riggs]

Just because:

| awk 'NR == 3 {print}'