wc

[Prabhu_7]

wc -l filename.txt

gives me ,
8 filename.txt

i want it to return only 8.
i want to check no of lines of one file with other one.

like ,
If wc -l f1.txt > wc -l f2.txt

[PIYUSH D. PATEL]

wc -l filename.txt | awk '{print $1}'

HTH,
Piyush

[Mark Greene_1 · Accepted solution]

try this:

if [ `cat f1.txt|wc -l` -gt `cat f2.txt|wc -l` ]; then

do stuff for greater than condition here

else

do stuff for not greater than condition here

fi

Note that I used the grave (backquotes) in the if statement.

HTH
mark

[Jeff Schussele]

Hi Prabhu,

Try this:

wc -l filename.txt | awk '{ print $1}'

HTH,
Jeff

[Helen French]

Try this:

# wc -l vg00.map |awk '{print$1}'

[PIYUSH D. PATEL]

wc -l f1.txt | awk '{print $1}' > wc -l f2.txt | awk '{print $1}'

Sorry for the second post....

HTH,
Piyush

[Dario_1]

Hi!!

How about:

cat filename.txt | wc -l

Regards,

DR

[Helen French]

Oops .. replace vg00.map with your file_name. I just copied the command which I tried =))

[James R. Ferguson]

Hi:

You could do:

# X=`wc -l f1.txt|cut -d" " -f1`

# Y=`wc -l f2.txt|cut -d" " -f1`

# if [ "${X}" -gt "${Y}" ]; then
...

Regards!

...JRF...

[James R. Ferguson]

Hi (again):

Of course, if you prefer:

# [ `wc -l f1.txt|cut -d" " -f1` -gt `wc -l f2.txt|cut -d" " -f1` ] && echo "f1 has more lines than f2"

Regards!

...JRF...