which users in a group?

[Enrico Venturi]

Hello guys,
how can I get from command line the users belonging to a group??

thanks
Enrico

[Pete Randall]

grep "group name" /etc/group


Pete

[Enrico Venturi]

Yes... eh eh eh...
I meant: some commands giving a list of users, and not just a string like dba::202:bmml,alcatel,snml ...
I'd prefere as output:
bmml
alcatel
snml

[Pete Randall]

Well, there is the groups command but that's not exactly what you're looking for, more like the opposite of what you're looking for. It looks like you might have to come up with a C program using getgrent().


Pete

[Peter Nikitka]

Hi,

use the 'groups' command:
groups : my groups I am member at
groups usernam

see 'man groups'

mfG Peter

[A. Clay Stephenson]

Try "logins -m".

Here's another approach that will list:
UserGroup1Group2 ...

#!/usr/bin/sh
logins | awk '{print $1}' | while read U
do
echo "${U}\t\c"
groups -l ${U} | while read G
do
echo "${G}\c"
done
echo
done

[Sandman! · Accepted solution]

Try the awk construct below:

# awk -F: '$1=="dba" {for(i=1;i<=split($4,z,",");++i) print z[i]}' /etc/group

[Victor BERRIDGE]

Greetings,

What about:
grep /etc/group|cut -d : -f 4|sed y/,/\\n/


All the best
Victor

[Peter Nikitka]

Sorry,

just realized, what you really want.
From a CLI sight of view, it depends which name resolution is set in ns_switch.conf: files, NIS, ...
It seems not deifficult to me. to modify my NIS-example for other resolution types:
(ypmatch GRPNAM group.byname; ypcat passwd) |
awk -F: 'NR==1 {group=$1;gid=$3;i=split($4,grp,",");next}
$4==gid {grp[++i]=$1}
END {if(i) {for(j=1;j<=i;j++) print grp[j]}}'

mfG Peter

[OldSchool]

for a in `grep /etc/group | cut -f 4 -d : | sed "s/,/ /g'`
do
echo $a
done

[Sp4admin]

Hello,

just do a long listing or grep for the group.

ll /etc/groups

grep group name /etc/groups

sp,