why awk gives output as exponential format output

[moonzh]

I wrote one shell script to get swap size, as below

echo "SWAPSIZE="`/usr/sbin/swapinfo -d | awk 'BEGIN { s=0 } { s=s+$2 } END { p
rint s }'`

In my HP-UX V11.00, it displays result as integer SWAPSIZE=786432.

But at customer's system, the output is exponential format as SWAPSIZE=1.04858e+06

I do not know why? I do want the output is integer. Can anybody help me?

[A. Clay Stephenson]

change your awk print to a printf ("%d\n",s)

[Peter Nikitka]

Use 'printf' instead of 'print', so you can pass a format statement:
/usr/sbin/swapinfo -d | awk 'BEGIN { s=0 }
{s+=$2}
END {printf ("SWAPSIZE=%d\n", s)}'

[moonzh]

Thx Peter & Clay! You guys solved my problem.