word splitting in shell

[Kourla]

Hi, can u please somebody tell how to split the word.

I wrote a shell script like this
#!/bin/sh
lv=`bdf |grep /var/opt/nokia |awk '{print $1}'`

In the lv variable I will get some string like "/dev/vg01/lvol2", from this string i have get "vg01" to some other variable.

If is is silly, please don't laugh on me because i am new to shell programming (:

[Sridhar Bhaskarla · Accepted solution]

Hi,

Use the seperator "FS" to achieve what you want. For ex., if you want to get only the Logical volume, you would do

bdf |grep /var/opt/nokia |awk '{print $1}'|awk '{FS="/";print $4}'

Use 'df' instead of 'bdf'. If your lvol name is too long, then you may not get what you want.

If you df, you should grep for the second column and then filerout what you want using the above logic.

-Sri

[Sridhar Bhaskarla]

Hi (Again),

BTW, if you want to get 'vg01' out of it, you will use '{FS="/";print $3}'

-Sri

[Jeff Schussele]

Hi Kourla,

Try this

bdf |grep /var/opt/nokia | cut -f 3 -d "/"

This should yield the VG name w/o having to awk. Of course, you could assign the output to a var.

HTH,
Jeff

[James R. Ferguson]

Hi:

'cut' will do here:

# VAR=`echo ${lv}}cut -f3 -d/`

Regards!

...JRF...

[Robert-Jan Goossens]

Hi,

bdf |grep /var/opt/nokia |awk '{FS="/";print $3}'

Robert-Jan.

[Dietmar Konermann]

I like using shell built-ins, especially for scripts that run frequently. fork/exec is expensive... and things sum up.

vg=${lv#/dev/}&& vg=${vg%/*}

Best regards...
Dietmar.

[Al Langen_1]

Nobody suggested split:

Instead of print $1, use split($1, arg, "/"]);print arg[3]

[Donny Jekels]

Al,

split works well, another way would be

lv=$(bdf | grep /var/opt/nokia | awk -F/ '{print $1}')

6 ways to skin a cat :o)