Writing a Script: du -k

[sai.prashant]

Hello,
Please helpme out in writing a script for the below scenario:

I have /Home directory under which i have all the User's Home directory as shown below. I have to write a script which should generate an output showing User Home Directory, Disk Space Used in KB, % Disk Space Used in descending order.

bdf command ouput for /Home:
/vol/vol1/home/tatc-in 73400320 63090040 10310280 86% /tmp_mnt/home/

Directories under /Home:
cmuluktl d03013 d03019 mappukut sprashan
DEL1.KAL d03001 d03014 d03020 mprakash sramanat
FINAL d03004 d03015 d03021 report_disk twr16
USftp d03005 d03016 d03023 sdhondi twr17
anandam d03009 d03017 indiaftp skondapa vbojja
apemmara d03010 d03018 kkomati smasabat

Thanks,
Sai

[Bharat Katkar]

Hi Sai,
# du -k | sort -k 1,1
This works for me.

for e.g.

# pwd
/home
# du -k
0 ./lost+found
8 ./one
8 ./two
16 .
# du -k | sort -k 1,1
0 ./lost+found
16 .
8 ./one
8 ./two
# ls -al
total 16
drwxr-xr-x 5 root root 96 Aug 11 12:54 .
drwxr-xr-x 15 root root 8192 Aug 10 19:02 ..
drwxr-xr-x 2 root root 96 Aug 9 18:12 lost+found
drwxrwxrwx 2 root sys 96 Aug 11 12:54 one
drwxrwxrwx 2 root sys 96 Aug 11 12:54 two
#

Regards,

[Jose Mosquera]

Hi,


Try this script:

#!/sbin/sh
OUTPUT=" Kb Directory"
DIRS=`ll|grep ^d|awk '{ print $9}'`
for DIR in $DIRS
do
OUTPUT="$OUTPUT\n`du -ks $DIR`"
done
echo "$OUTPUT"|sort -n

Rgds,

[Bharat Katkar]

Sai,
sorry for that.. little confusion...
This should work.
# du -k | sort -k 1n,1

Regards,

[Michael Tully]

There are a couple of perl offerings in the old "system admin" scripts thread.

See ernesto's here:
http://forums1.itrc.hp.com/service/forums/questionanswer.do?threadId=51050

and Ben Sachs
http://forums1.itrc.hp.com/service/forums/parseCurl.do?CURL=%2Fcm%2FQuestionAnswer%2F1%2C%2C0x836cc1c4ceddd61190050090279cd0f9%2C00.html&admit=716493758+1092210687681+28353475

There is a gold mone of scripts in the 3 threads.

[Michael Campbell]

Sai

Here's a handy one:

rm /tmp/du_dir_list 2>/dev/null
rm /tmp/du_dir_list2 2>/dev/null
echo " "
echo "FILES:"
echo " "
ll | grep -v ^d |sort -k 5n

ll | grep ^d |cut -c59- > /tmp/du_dir_list
if [ -s /tmp/du_dir_list ]
then
echo " "
echo "DIRECTORIES (in Kb):"
echo " "
for dirname in `cat /tmp/du_dir_list`
do
du -sk $dirname | awk '{ printf("%8d %s\n",$1,$2) }' >>/tmp/du_dir_list2
done
sort /tmp/du_dir_list2
else
echo " "
echo "There are no Directories:"
echo " "
fi
rm /tmp/du_dir_list 2>/dev/null
rm /tmp/du_dir_list2 2>/dev/null
echo " "
bdf .

[MarkSyder]

To sort the directories in descending order:

du -k|sort -k1,1nr

The nr specifies numerical reverse (default is smallest first)

Mark Syder (like the drink but spelt different)

[Bharat Katkar]

http://forums1.itrc.hp.com/service/forums/helptips.do?admit=716493758+1085211538437+28353475#33

[Muthukumar_5]

You can do with the following script simply

#!/usr/bin/ksh

for user in `ls /home`; do

fssize=`bdf /home | grep -v "^Filesystem" | awk '{ print $2 }'`
homesize=`du -ks /home/$user | grep -v "^Filesystem" | awk '{ print $1 }'`

if [[ $homesize -ne 0 ]]
then
per=$(echo "$homesize $fssize" | awk '{ print $1/$2*100 }')
else
per=0
fi

home=`du -ks /home/$user | awk '{ print $2 }'`

echo "$home $homesize $fssize $per %"
done >> /tmp/form.log
echo "HOME DIRECTORY USAGE DISK SPAGE %DISK SPACE USAGE"
cat /tmp/form.log | sort -r -k 4
rm -f /tmp/form.log

## end ###

Output:
=======
# ksh /tmp/form.ksh
HOME DIRECTORY USAGE DISK SPAGE %DISK SPACE USAGE
/home/muthu 3152 32768 9.61914 %
/home/testusr 32 32768 0.0976562 %

Regards
Muthu