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01-07-2002 10:44 AM
01-07-2002 10:44 AM
			
				
					
						
							X emulator workload.
						
					
					
				
			
		
	
			
	
	
	
	
	
			
				
					
					
						Hi Team:
We are using xemulator(to launch the app from the pc). Apps run on N-class. when the users closes the application on the PC there is a runaway process on the N-class. We got a suggestion to publish the application from xterm(this would make the xterm run inside the xemulation software). Is this an acceptable solution. I thought it was the xemulator's job to run the app. Will this consume more resource with expected users around 100?
Please Advise.
Brian.
		
		
	
	
	
We are using xemulator(to launch the app from the pc). Apps run on N-class. when the users closes the application on the PC there is a runaway process on the N-class. We got a suggestion to publish the application from xterm(this would make the xterm run inside the xemulation software). Is this an acceptable solution. I thought it was the xemulator's job to run the app. Will this consume more resource with expected users around 100?
Please Advise.
Brian.
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01-07-2002 12:41 PM
01-07-2002 12:41 PM
			
				
					
						
							Re: X emulator workload.
						
					
					
				
			
		
	
			
	
	
	
	
	
			
				
					
					
						Brian,
Depending on the way you call the xload type app from inside a shell (xterm), then when you log out it will tell you that you have a running process, if you type exit again, the shell will end but the xload type app will not stop, thus you will be back at the same point. So there is the possibility that you would not solve your problem.
If you call the xload app with xload & or nohup xload then this possiblity exists.
If you call the xload app with just xload then the process will be in the foreground of the shell and will have to be exited before the shell can be ended.
I hope I have read your description properly and have explained things a bit.
GL,
C
		
		
	
	
	
Depending on the way you call the xload type app from inside a shell (xterm), then when you log out it will tell you that you have a running process, if you type exit again, the shell will end but the xload type app will not stop, thus you will be back at the same point. So there is the possibility that you would not solve your problem.
If you call the xload app with xload & or nohup xload then this possiblity exists.
If you call the xload app with just xload then the process will be in the foreground of the shell and will have to be exited before the shell can be ended.
I hope I have read your description properly and have explained things a bit.
GL,
C
	"In theory, there is no difference between theory and practice. But, in practice, there is. " Jan L.A. van de Snepscheut
			
			
				
			
			
			
			
			
			
		The opinions expressed above are the personal opinions of the authors, not of Hewlett Packard Enterprise. By using this site, you accept the Terms of Use and Rules of Participation.
		
	
	
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