Dormant Users

[Vipulinux]

Hi
Need a shell script that can tell the users who have not logged into the box since X no. of days eg 90 days ..

Need to work on login and last command

Cheers
Vipul

[Ivan Ferreira]

Try something like this (I have not tested):

# Not logged in days
NOT_LOGGED_DAYS=90

# Get NOT_LOGGED_SEC seconds

NOT_LOGGED_SEC=`date --date "$NOT_LOGGED_IN days ago" +%s`

# Last logged

LAST_LOGGED=`date --date "$(last -1 $1 | grep -v begins | awk '{ print $4,$5 }')" +%s`

if [ $LAST_LOGGED -lt NOT_LOGGED_SEC ]; then
echo "The user $1 did not logged in $NOT_LOGGED_DAYS days"
else
echo "This user is not a dormitant user"
fi

Usage:

script_name username

[Vipulinux]

Hi Ivan

Thanks for your response.
I dont want to do it one by one.
I need a script that compares /etc/passwd and logins output and shows those users who have not logged in since 90 days..
Thanks

[Rick Garland · Accepted solution]

Here is a perl script that will list the 'last' info for all users. From this list you can decipher who has/has not logged in for last 90 days.

You could pipe this output through sort, or include the perl code to sort, to get your requested info.

[Vipulinux]

Hi Rick

The script is great!!!
just wonder if it could show the year of login as well i.e whether it was 2005 or 2006

Human Nature: Always demanding!!
Cheers

[Rick Garland]

last does not display the year so some sort of rotation scheme (of the wtmp file) is necessary to prevent the overlap of months

[Vipulinux]

Thanks for the replies!!

[Vipulinux]

Hi All

there is 1 script but doesnt seem to give corret results..
is there a script that give full details of users who have'nt logged in since x no of days and also when was there last login etc..


cheers