get certain fields within an output

[lawrenzo_1]

Hi all,

more awk help needed please:

I want to print some information in awk:

info1 info2 info3 info4
info5 info6 info7 info8
info9 info10 info11 info12
info13 info14 info15 info16

this is an example output ...

how do I use awk to print info4, info8 and info 12 please, the only common denominator in the sting is PP however this string will appear in info5 and info9 for example.

hope this makes sense!

Thanks in advance.

Chris

[Jeff_Traigle · Accepted solution]

In your case, the content of the field doesn't matter. You're wanting the fourth field of each line. Assuming the data is in a file called datafile:

awk '{print $4}' datafile

[lawrenzo_1]

doh,

as easy as that ....

I knew this but wasnt thinking ...

Thanks for the help.

[perumal_2]

Hi Chris

In awk $"column number" displays the whole column values.
lets say for example you wnat to print 4th cloumn you may use
awk '{print $4}'. I assume from your query that you wanted to print the whole 4th column, though you had missed info16

rgds
perumal

[SANTOSH S. MHASKAR]

Hi,

Use following if ur i/p to awk is

info1 info2 info3 info4
info5 info6 info7 info8
info9 info10 info11 info12
info13 info14 info15 info16
--------------------------
# awk '{print $4}'
--------------------------

but I don't understand what do u mean by this

--------------------------
how do I use awk to print info4, info8 and info 12 please, the only common denominator in the sting is PP however this string will appear in info5 and info9 for example.
---------------------------

Pl. elaborate above.

[lawrenzo_1]

ok thannks guys,

I wasnt thinking straight:

my solution is

awk '/PPs:/ {print $4,$5": "$6}' datafile

[lawrenzo_1]

ty