invoking a function with parameter

[Maciej Szewczykowski]

hi all.
how to invoke a function so it takes certain values as parameters?
the point is: i've got a function that work with two variables (v1, v2). i'd like to make it work each time with different values of these variables. where should the function take values from (command line? file?)
how to make it work?

[Mark Grant]

Lets assume you mean a shell script for the moment. When you call the function, just use your values as arguments and within the function reference them as $1 $2 etc etc.

Hope this helps.

[Maciej Szewczykowski]

Mark, could you please write a short example? (i mean how to send values to the function)

[Mark Grant · Accepted solution]

function myecho {
echo $1
}

myecho hello
exit

I don't know if you can prototype functions so its safer to just declare the functions first.

[Jerome Henry]

Write :
v1=3
v2=7
echo $v1
3
echo $v2
7

hth

J

[Maciej Szewczykowski]

quick question - quick answer. thanks a lot guys.

[Graham Cameron_1]

Didn't you ask this yesterday in the HP forums ??
http://forums1.itrc.hp.com/service/forums/questionanswer.do?threadId=233360
--
Anyway, within the function, just refer to $1, $2 as your parameters, and call it using syntax "yourfunc p1, p2".
Example: function leave takes an optional single parameter
--
function leave {
[ -n "$1" ] && exit_cd=$1
exit $exit_cd
}
-- and can be called in 2 ways --
leave 1
leave
--
--Graham

[Mark Grant]

And another, just to show some looping


function addten {
b=`expr $1 + 10`
echo "$1 plus 10 is $b"
}

for i in 10 23 4 65
do
addten $i
done

[Maciej Szewczykowski]

that's right. thank you once more.