wildcards in awk scripting, how use them?

[debian111]

Hi people,
I have statement
awk ' { if(( $9=90*) && ($9=91*) && ($9=92*)) print $9 }'> /home/some_file.txt
where with * I want to select all numbers which begin with 90, 91, 92, and no mater which number is later. There is 4 numbers after 90, 91, 92.

how use wild wildcards in this case to print out all that numbers.

[Alexander Chuzhoy]

Use this:

awk ' { if( $9 ~ /^9[123]+[0-9]+/) print $9 }'> /home/some_file.txt

[Alexander Chuzhoy · Accepted solution]

Sorry, I used 123 instead of 012. Here's a corrected answer:

awk ' { if( $9 ~ /^9[012]+[0-9]+/) print $9 }'> /home/some_file.txt

[spex]

Hi,

awk '{ if( $9 ~ /^9[012][0-9]{4}$/) print $9 }' < in.txt > out.txt

PCS

[debian111]

Thanks