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тАО08-18-2022 06:32 AM - last edited on тАО08-21-2022 08:48 PM by support_s
тАО08-18-2022 06:32 AM - last edited on тАО08-21-2022 08:48 PM by support_s
Hello everyone,
I have a question about Simplivity usable space in 3 node clusters.
As I understand if in 2 node cluster reported physical space is 59TB, that means the actual usable space is ~29TB (50% goes HA), similar to RAID1
In 3 node case, does RAID5 level of usable space and availability apply? Meaning only 1 node can fail and usable space would 2/3 of total physical space and 1/3 to HA?
Solved! Go to Solution.
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тАО08-18-2022 07:09 AM - edited тАО08-18-2022 07:11 AM
тАО08-18-2022 07:09 AM - edited тАО08-18-2022 07:11 AM
Re: 3 Node Simplivity cluster usable capacity
Here is the general formula I found to use when sizing for the SimpliVity DVP capacity efficiency:
( Production data + (production data * percent expected growth/100) ) / 2.25 efficiency
For example a customer with 125 TB of data and expected growth of 25%:
( 125 + ( 125 * 25/100 ) ) / 2.25 = ~69.44 TB
If a node failed, I would remove that amount of capacity from the equation-
Here is a good web page that may help you with usable capacity.
http://www.vhersey.com/2016/05/16/simplivity-effective-storage-capacity/
While I am an HPE Employee, all of my comments (whether noted or not), are my own and are not any official representation of the company

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тАО08-18-2022 09:06 AM - edited тАО08-18-2022 10:06 AM
тАО08-18-2022 09:06 AM - edited тАО08-18-2022 10:06 AM
SolutionHi Steez
Hope you are doing well.
We always keep two full copies of hives that is why It will be a total capacity / 2
OR
Usable capacity per cluster =[ #nodes * (Usable capacity per node)] /2
Hope this helps.!!
Regards
Mahesh.
I work at HPE
HPE Support Center offers support for your HPE services and products when and how you need it. Get started with HPE Support Center today.
[Any personal opinions expressed are mine, and not official statements on behalf of Hewlett Packard Enterprise]
