2 clusters on one machine.

[Schelstraete Bart_1]

Hello,

Is it possible to configure 2 different clusters on one machine.
For example:
machine A + machine B = Cluster1
machine B + machine C = Cluster2

So on machine B, 2 different clusters needs to run.
It tried this, but if I'm applying 'Cluster2', he tries to rename Cluster1.

Is this possible?

[Jeff Schussele]

Hi Bart,

Sorry no, this is not possible.
Only one cluster per machine allowed.
But the number of packages allowed is quite high & you should be able to achieve what you want be creatively configuring the packages to run what you want, *where* you want.

Rgds,
Jeff

[Kent Ostby]

No its not.

Perhaps an approach you could take is to step back a level.

Instead of having two clusters that perform different things, you could have two PACKAGES that perform different things.

Maybe Package1 runs on Machine A and fails over if necessary to Machine B while Package 2 runs on Machine C and also fails over to Machine B if necessary.

So machine B backs up each of these boxes.

Best regards,

Kent M. Ostby

[Patrick Wallek]

I don't think this is possible. I believe a machine can only be a part of 1 cluster at a time.

[Massimo Bianchi]

Hi,
one server can belong to one and only one cluster.

You cannot do that.
But you can build a 3 server cluster and use packages.

Massimo

[Duncan Edmonstone]

If the machines in question support vPAR or nPAR partitions then you *could* do this in theory... machine B would have to be split into 2 seperate partitions (two seperate OS images). Otherwise as others have stated the best option is a single cluster of all three systems with 1 package that runs on only A and B and another that runs on only B and C.

HTH

Duncan

[Geoff Wild]

Just back from MC/SG II course - the answer is no.

As otheres have suggested, make a single cluster with 3 nodes. Make B your "standby" node for all packages. Have some packages run on primary node A and others on with C as the primary. You can configure these packages so that they only run on either A and B or C and B.

Rgds...Geoff