awk with two variables in sh script

[Bernd Dittmar]

Must use sh!
As $1 i get a string with variable stringlength.
With awk '{print length($1)}' i want to get the stringlength of $1 in an variable like bl.
This variable has to be used in the script.
How the variable can be used from stdin?

[Thierry Poels_1]

hi,

echo $1
bl=$(echo $1 | awk "{print length(\"$1\")}")
echo $bl

good luck,
Thierry.

[Jean-Louis Phelix]

Hi,

I wouldn't use awk in this case :

#!/usr/bin/sh
L=${#1}
echo "length of '$1' is $L"

would be easier ...

Regards.

[Steve Steel]

Hi

typeset -i length=$(echo $1|wc -c)-1
echo $length


length is then the integer value of the string length of $1


Steve Steel

[John Meissner]

Bernd... sounds like homework
and if you NEED to use awk:

string=$1
bl=$(echo $string | awk '{print $1}' | wc -m)
echo $bl

of course this can be done without awk completely

bl=$(echo $1 | wc -m)

[Mike Miller_8]

Try the following . . .

let c=$(echo $1 | wc -m)-1

= Mike =

[Jordan Bean]

If you want to work with a list of strings on stdin, then follow this model:

#!/usr/bin/sh
while read string
do
length=${#string}
echo $length $string
done