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01-15-2004 08:22 AM
01-15-2004 08:22 AM
I want to set a job to run on the last day of each month. Accordingly, I have crontab lines for
31st day of months 1,3,5,7,8,10,12
30th day of months 4,6,9,11
28th, 29th day of month 2
I put in 28th and 29th to catch leap years. If the current year does not have a Feb 29th, will crontab blow up, or just not run twice that month?
31st day of months 1,3,5,7,8,10,12
30th day of months 4,6,9,11
28th, 29th day of month 2
I put in 28th and 29th to catch leap years. If the current year does not have a Feb 29th, will crontab blow up, or just not run twice that month?
Solved! Go to Solution.
1 REPLY 1
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01-15-2004 08:29 AM
01-15-2004 08:29 AM
Solution
No, cron will handle that just fine. However, you could do this with one entry on the 28-31 of EVERY month and then let the script itself determine if this is the last day of the month.
#!/usr/bin/sh
if [[ $(caljd.sh -M) -ne $(caljd.sh -n 1 -M) ]]
then
echo "Last Day of Month; do your thing"
fi
Here's caljd.sh. Invoke as caljd.sh -u for full usage and to find out what it does.
#!/usr/bin/sh
if [[ $(caljd.sh -M) -ne $(caljd.sh -n 1 -M) ]]
then
echo "Last Day of Month; do your thing"
fi
Here's caljd.sh. Invoke as caljd.sh -u for full usage and to find out what it does.
If it ain't broke, I can fix that.
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