date script

[Dottie Hamilton]

I am trying to write a script that will delete a file with the extention of the prior days date and everything that I have tried doesn't work. I don't want to delete the file with the current date as its extention.
What am I missing.

thanks

[Steve Steel]

Hi


Example please of extension used
for previous and todays date plus what you tried

You can always touch a file with an mtime of today at 06:00 and then find files older
and delete them.Then remove touch file.


Steve Steel

[Alexander M. Ermes]

Hi there.
Try this find statement :

find /u004/ftp/cash/if/in/cop/archive/ -name icstc_v100_a??????_0??.??-??-??
-exec rm {} \;
You can replace the last question marks by a parameter, that you can enter.
Rgds
Alexander M. Ermes

[Justo Exposito]

Hi Dottie,

I suppouse that you have files with names like this:

filename.yyyymmdd

If it is you can do a script that keep the today date and rm all the files with an extension minor than today.

Something like this:

cd your directory
date=$(date +%Y +%b +%d)
for i in `ls`
do
extension=$(echo $i | cut -d. -f2)
if [ $extension -lt $date ]
then
file="\*"+"\."+${extension}
rm ${file}
fi
done

Regards,

Justo.

[Steve Steel]

Hi

or

today=todays_extension
find /your_dir -type f|grep -v $today|xargs rm

Will do it if you want to remove all but todays files.

or
find /yourdir -type f -mtime +1|xargs rm

kill more than 1 day old

Steve Steel

[A. Clay Stephenson]

Hi Dottie:

I've attached a date script called caljd.sh; this will do almost any date problem; in this case it's overkill but this is my date hammer and every date problem is a nail.

FILENAME=myfile
SUFFIX=$(caljd.sh -y -s $(caljd.sh -p 1))
FULLNAME="${FILENAME}.${SUFFIX}"
This will result in a filename for the previous day of "myfile.20020123".

The inner caljd.sh uses the -p 1 argument to find the julian day 1 day previous. The outer call the converts that julian day into YYYY MM DD (the -y argument) and the -s removes the spaces to yield "YYYYMMDD". Invoke caljd.sh -u for full usage. With this you can skip weekends or holidays, leap years don't matter, or change the number of days previous.

If you start using this script, I think you will use nothing else for a date calculation within a script.

Regards, Clay

[Steven Sim Kok Leong]

Hi,

If you have the date in the format: filename.yyyymmdd. You can write your script to make use of the fact that the files are sorted numerically in ls.

This script will remove all filename.* logs except the latest log (ie. today's log):
==========================================
#!/sbin/sh

current=`ls filename.*|tail -1`

for file in filename.*
do
if echo $file | grep $current
then
: # today's log, do nothing
else
rm $file # remove this log
fi
done
==========================================

Hope this helps. Regards.

[Dottie Hamilton]

This is what I am trying to use; what have I got wrong?#!/bin/sh

cd /hbo/audittest
find . -type f -mtime -1 -exec rm -f {} \;

thanks for everyones help

[A. Clay Stephenson]

Hi Dottie:

In that case, you need to change your -1 to +1 (older than 1 day). I a little surprised because this stuff has nothing to do with suffixes as your original post indicated.