delete

[Indrajit Bhagat]

can you help me in a command to delete the file of Aug 31.
-rw-r--r-- 1 porabat prod 1004 Aug 31 07:40 IFCHAPSIN1070831072920310807074046.dat.Z
-rw-r--r-- 1 porabat prod 1695 Aug 31 07:41 IFCHAPSIN1070831070023310807074105.dat.Z
-rw-r--r-- 1 porabat prod 5095 Aug 31 07:41 IFCHAPSIN1070831062919310807074118.dat.Z
-rw-r--r-- 1 porabat prod 109 Aug 31 07:41 CHAPSIn_Error31AUG2007074117.csv.Z
-rw-r--r-- 1 porabat prod 109 Aug 31 07:41 CHAPSIn_Error31AUG2007074103.csv.Z
-rw-r--r-- 1 porabat prod 109 Aug 31 07:41 CHAPSIn_Error31AUG2007074134.csv.Z
-rw-r--r-- 1 porabat prod 1084 Aug 31 08:11 IFCHAPSIN1070831080002310807081111.dat.Z

[Pete Randall]

for FILE in `ll |grep "Aug31" |awk '{ print $9 }'`
do
rm $FILE
done

You might want to test by replacing "rm" with "ll" first.


Pete

[Laurent Menase]

ls -l | while read a b c d e f g h i
do
if [ ! -f $i ]
then
continue
fi
if [ "$f" != "Aug" -o "$g" != "31" ]
then
continue
fi
echo "# $(ls -l $i)"
echo "rm $i"
done > myfiletoexecute

check the myfiletoexecute, if it looks ok
sh myfiletoexecute

[MarkSyder]

Pete's suggestion is what I would use, except you appear to have more than one file dated 31 Aug. Your question implies that you only want to delete one file, so I would use rm -i so you will be asked to confirm deletion.

Mark Syder (like the drink but spelt different)

[Pete Randall]

Mark makes a good point concerning how many files are to be deleted. My answer assumes that all files dated Aug 31 are to be deleted. If that is not what was intended, then the question needs to be re-stated.


Pete

[Arturo Galbiati]

rm $(ls -l |awk '/ Aug / {print $9}')
use rm -i if you want to confirm each signle file.
HTH,
Art