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04-15-2004 07:39 AM
04-15-2004 07:39 AM
I am trying to list files whose names contain 8 consecutive digits. According to "man 5 regexp", command "ls *[0-9]\{8\}*" should work, but it does not. What is the proper syntax for finding regular expression repeated occurances? Thank you.
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04-15-2004 08:25 AM
04-15-2004 08:25 AM
Solution
Filename wildcards aren't the same as regular expressions.
For example a "." is any character in regexp, while "?" is any character in wildcards.
To list files with 8 digits-
ls *[0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9]*
HTH
-- Rod Hills
For example a "." is any character in regexp, while "?" is any character in wildcards.
To list files with 8 digits-
ls *[0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9]*
HTH
-- Rod Hills
There be dragons...
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04-15-2004 08:32 AM
04-15-2004 08:32 AM
Re: finding regular expression repeated occurances
Because the shell does not fully implement regular expressions
to use your example
ls *[0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9]* would have worked.
Commands like grep -E, sed, and awk fully implement regular expressions and Perl extends RE's to almost ludicrous (albeit useful) levels.
to use your example
ls *[0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9]* would have worked.
Commands like grep -E, sed, and awk fully implement regular expressions and Perl extends RE's to almost ludicrous (albeit useful) levels.
If it ain't broke, I can fix that.
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