Grep - for get words with spaces

[Manuales]

HI...
When i try to pipe "May 1"i can not do it through grep command:

o=`perl -MPOSIX -le 'print strftime "%b %e",localtime(time-86400)'`
echo "cat /var/adm/lp/log | grep ""$o"""
t /var/adm/lp/log | grep May 1

Result:
cat /var/adm/lp/log | grep ""$o""
grep: can't open 1

apparently grep only is taking: May .
how can i do (what coding) for grep command takes "May 1"


thanks.

[James R. Ferguson · Accepted solution]

Hi Manuales:

# grep "$0" /var/adm/lp/log

[...and please don't forget to evaulate your other queries :-) ]

Regards!

...JRF...

[Manuales]

and if i have to do grep to a variable and not file? how do i have to do it?

[James R. Ferguson]

Hi (again):

# var="May 1"
# thing="May 1"
# echo "${var}" | grep "${thing}"
May 1

Regards!

...JRF...

[Steven Schweda]

You seem to have many basic questions about
shell scripts. Have you considered reading
a book on UNIX shell scripting?

[Manuales]

your answer helped me a lot:
i had to put double ""

b=$(echo $hola | grep ""${a}"" | grep -v `hostname`)

thanks a lot.

[Manuales]

SORRY
THIS WAS THE SOLUTION:

b=$(echo "$hola | grep "\""${a}""\" " | grep -v `hostname`)

[Kapil Jha]

have a look over egrep as well!!
BR,
Kapil