HPE GreenLake Administration
- Community Home
- >
- Servers and Operating Systems
- >
- Operating Systems
- >
- Operating System - HP-UX
- >
- Re: Help with SED and variable for regexpr
Operating System - HP-UX
1828366
Members
2861
Online
109976
Solutions
Forums
Categories
Company
Local Language
back
Forums
Discussions
Forums
- Data Protection and Retention
- Entry Storage Systems
- Legacy
- Midrange and Enterprise Storage
- Storage Networking
- HPE Nimble Storage
Discussions
Forums
Discussions
Discussions
Discussions
Forums
Discussions
back
Discussion Boards
Discussion Boards
Discussion Boards
Discussion Boards
- BladeSystem Infrastructure and Application Solutions
- Appliance Servers
- Alpha Servers
- BackOffice Products
- Internet Products
- HPE 9000 and HPE e3000 Servers
- Networking
- Netservers
- Secure OS Software for Linux
- Server Management (Insight Manager 7)
- Windows Server 2003
- Operating System - Tru64 Unix
- ProLiant Deployment and Provisioning
- Linux-Based Community / Regional
- Microsoft System Center Integration
Discussion Boards
Discussion Boards
Discussion Boards
Discussion Boards
Discussion Boards
Discussion Boards
Discussion Boards
Discussion Boards
Discussion Boards
Discussion Boards
Discussion Boards
Discussion Boards
Discussion Boards
Discussion Boards
Discussion Boards
Discussion Boards
Discussion Boards
Discussion Boards
Discussion Boards
Discussion Boards
Blogs
Information
Community
Resources
Community Language
Language
Forums
Blogs
Go to solution
Topic Options
- Subscribe to RSS Feed
- Mark Topic as New
- Mark Topic as Read
- Float this Topic for Current User
- Bookmark
- Subscribe
- Printer Friendly Page
- Mark as New
- Bookmark
- Subscribe
- Mute
- Subscribe to RSS Feed
- Permalink
- Report Inappropriate Content
02-26-2010 09:37 AM
02-26-2010 09:37 AM
Hi,
I want to be able to find a string and then print the next line. The string is a variable. If I hard code it in the below line, it works but it won't take a variable. I have tried double quotes; single quotes; back slashes, etc. Maybe not the right combo or syntax though.
cat file|sed -n '/$VAR/{n;p;}'
I want to be able to find a string and then print the next line. The string is a variable. If I hard code it in the below line, it works but it won't take a variable. I have tried double quotes; single quotes; back slashes, etc. Maybe not the right combo or syntax though.
cat file|sed -n '/$VAR/{n;p;}'
whatever
Solved! Go to Solution.
3 REPLIES 3
- Mark as New
- Bookmark
- Subscribe
- Mute
- Subscribe to RSS Feed
- Permalink
- Report Inappropriate Content
02-26-2010 10:16 AM
02-26-2010 10:16 AM
Solution
Hi:
You need double quotes to allow the shell to expand the variable:
# VAR=whatever
# sed -n "/$VAR/{n;p;}" file
Notice that the 'cat' into a pipe is superfluous. The 'sed' reads STDIN just fine, saving you a process.
Regards!
...JRF...
You need double quotes to allow the shell to expand the variable:
# VAR=whatever
# sed -n "/$VAR/{n;p;}" file
Notice that the 'cat' into a pipe is superfluous. The 'sed' reads STDIN just fine, saving you a process.
Regards!
...JRF...
- Mark as New
- Bookmark
- Subscribe
- Mute
- Subscribe to RSS Feed
- Permalink
- Report Inappropriate Content
02-26-2010 10:24 AM
02-26-2010 10:24 AM
Re: Help with SED and variable for regexpr
Yay...thanks!!
whatever
- Mark as New
- Bookmark
- Subscribe
- Mute
- Subscribe to RSS Feed
- Permalink
- Report Inappropriate Content
02-26-2010 12:44 PM
02-26-2010 12:44 PM
Re: Help with SED and variable for regexpr
Note: GNU grep has a -A # option to print context around your match.
The opinions expressed above are the personal opinions of the authors, not of Hewlett Packard Enterprise. By using this site, you accept the Terms of Use and Rules of Participation.
Company
Support
Events and news
Customer resources
© Copyright 2025 Hewlett Packard Enterprise Development LP