How can i exit a script when a sentence is true into a function?

[Manuales]

Hi ...
i have a script .. which is using a function as follows:

!#/usr/bin/sh
command1 ..
command2 ..
function ...
command3 ..
command4 ...

how can i do to finish the script when a sentence is true into function?
i mean ..
if i sentence is true into function, how can i break the script, i mean finishe it without run command3 and command4? with exit? with break? what command do i must use ....?

Thanks,
Manuales

[Ivan Ferreira · Accepted solution]

In your function, after your contition verification, add

exit 0

[Ivan Ferreira]

For example:

check(){
if [ "$1" = "bye" ]; then
echo "Bye Bye"
exit 0
fi
}
echo hello
echo hello
check hello
echo hello
echo hello
check bye
echo hello
echo hello


If you run the script you will get:

hello
hello
hello
hello
Bye Bye

That is, two hello before check, first check is false so won't exit, two more hello, second check is true so it exits and the last two hello are not printed.

[A. Clay Stephenson]

There are many ways to accomplish this but here is one approach:

Your function should have an explicit return statement

myfunct()
{
typeset -i FSTAT=0

if [[ ${1} -gt 5 ]]
then
FSTAT=1
fi
return ${FSTAT}
} # myfunct


typeset -i STAT=0
command1
command2
myfunction 10
STAT=${?} # capture status of last command/function
if [[ ${STAT} -ne 0 ]]
then
exit ${STAT}
fi
command3
command4

[Manuales]

Thanks all, i'll try when i have arrived at home, if i have a problem i'll writte again ..

thanks !!! :)

[Manuales]

THANKS ALL!!!!
THAT WORKED !!!

THANK YOU VERY MUCH !!!!
:0)

Manuales.