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04-19-2002 07:19 AM
04-19-2002 07:19 AM
Hello everyone,
I am working on a script to determine how long it has been since a file has been accessed. I have used "ls -lu filename" but that output is difficult to work with. Find only works over ranges of days but I need to know with better detail than that. Anyone know an easier method than ls -lu?
TIA, Neil
I am working on a script to determine how long it has been since a file has been accessed. I have used "ls -lu filename" but that output is difficult to work with. Find only works over ranges of days but I need to know with better detail than that. Anyone know an easier method than ls -lu?
TIA, Neil
It wasn't me.
Solved! Go to Solution.
2 REPLIES 2
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04-19-2002 07:28 AM
04-19-2002 07:28 AM
Solution
Hi Neil:
This is not too difficult and I already had a Perl script that was very close. I simply modified it with a '-e' argument to output epoch seconds. Try this:
FNAME=$1
shift
NOW=$(perl -e 'print time')
ACCESS_TIME=$(fileage.pl -a -e ${FNAME})
SECONDS=$(( ${NOW} - ${ACCESS_TIME) ))
echo "File ${FNAME} was last accessed ${SECONDS} ago."
You can, of course, divide ${SECONDS} into any other convenient unit of time.
Fileage.pl has quite a few other uses. Fileage.pl -u will give full usage.
Regards, Clay
This is not too difficult and I already had a Perl script that was very close. I simply modified it with a '-e' argument to output epoch seconds. Try this:
FNAME=$1
shift
NOW=$(perl -e 'print time')
ACCESS_TIME=$(fileage.pl -a -e ${FNAME})
SECONDS=$(( ${NOW} - ${ACCESS_TIME) ))
echo "File ${FNAME} was last accessed ${SECONDS} ago."
You can, of course, divide ${SECONDS} into any other convenient unit of time.
Fileage.pl has quite a few other uses. Fileage.pl -u will give full usage.
Regards, Clay
If it ain't broke, I can fix that.
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04-19-2002 12:10 PM
04-19-2002 12:10 PM
Re: How long since a file was accessed?
Thanks Clay. That was perfect!!!
It wasn't me.
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