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05-17-2004 07:30 PM
05-17-2004 07:30 PM
MTU size = 1500
netstat -I lan1 1
(lan1)->input output
packets packets
1889785720 1150376362
1889788666 1150378958
amount of transmission data per second in lan1 =
((1889788666-1889785720)+(1150378958-1150376362))*1500 = 8313000 byte
Could you tell me my arithmetic is right or wrong?
TIA
Joseph
Solved! Go to Solution.
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05-17-2004 07:46 PM
05-17-2004 07:46 PM
SolutionBoth things are different.
What we use to do is calculate the performance or speed of our network by ftp of any big files and it give you back the speed with which it was transffered.
Do it on Peak period, normal load and no load situations.
Hope this helps,
Regards
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05-17-2004 08:10 PM
05-17-2004 08:10 PM
Re: How to calculate the amount of transmission data per second
In your calculation you multiply the in and outbound packets' differences per interval with the maximum transfer unit of the NIC,
assuming all counted packets being this size.
I don't believe this is necessarily the case.
I'm sure the gurus will provide you a correct eplanation.
Maybe you could query the MIB stats through SNMP GET calls or do some packet sniffing to get a more detailed picture?
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05-17-2004 08:10 PM
05-17-2004 08:10 PM
Re: How to calculate the amount of transmission data per second
Thank you very much.
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05-17-2004 08:12 PM
05-17-2004 08:12 PM
Re: How to calculate the amount of transmission data per second
you may find a nice tool for benchmarking your NICs here:
http://www.netperf.org/netperf/NetperfPage.html