How to display last line with awk?

[ericfjchen]

awk 'NR==4{print $1}' /tmp/test.log
---
The above can display forth line of the file /tmp/test.log. How to display the last line... NR==?

Thanks

Eric

[Leif Halvarsson_2]

hi,

try

'END {print $1}'

[Kasper Hedensted]

Do you need to do this with awk ?

If not then use tail

tail -1 /tmp/test.log

Cheers,
Kasper

[Joseph Loo]

hi,

not sure how to use awk to display last line, but using tail:

# tail -n 1 /tmp/test.log

regards.

[Cem Tugrul]

Eric,

tail -1 /tmp/test.log

good luck,

[Rick Garland]

Use the tail command as mentioned.

tail -1

[Rick Garland]

Use the tail command as mentioned.

tail -1

This is 1 line to get what you want. Doing so with awk will be more lines and more complexity

[Kent Ostby]

Eric --

awk '{saveit=$0;}END{print saveit}' /tmp/test.log

[Sandman!]

Eric...tail is your best choice though you can use sed as well:

# tail -1

# sed -n '$p'

[Marvin Strong]

awk 'END{print $0}' file

will give you the entire last night of the file.

[Torsten.]

Hi Eric,

it depends from what you want to get.

awk 'END {print $1}' ... will give you a field (only) of the last "readable" line, but
awk 'END {print $0}' ... will give you the really last line - EOT (just something like nothing). tail is a good tool to get what you want.

HTH

[Sandman!]

The only way awk will show the last line has been mentioned by Kent i.e

# awk '{lst=$0} END{print lst}'

awk 'END {print $0}' # will not show the last line of the file.

[Leif Halvarsson_2]

Hi,
Yes,
awk 'END {print $0}' /tmp/test.log
don't work but,
awk 'END {print $1}' /tmp/test.log
does work (and, also $2 $3 etc.).

I used $1 as it was used in the initial example.
awk 'NR==4{print $1}' /tmp/test.log

[ericfjchen]

Thanks for your help.

Yes, the following can display the last line
------------
awk '{saveit=$0;}END{print saveit}' /tmp/test.log
------------
However, I would like to get the first field of the last line..... How can I do?

Thanks again

[Muthukumar_5]

Try as,

# awk 'END{ print $1 }' /tmp/test.log

hth.

[Sandman! · Accepted solution]

# awk 'END{ print $1 }' /tmp/test.log

will print the first field of the last line as will:

# tail -1 .profile | cut -d" " -f1

cheers!

[Leif Halvarsson_2]

Hi,
My previous reply do exact what you ask for, but, you can also try :

awk '{saveit=$0;}END{getline saveit ; print $1}' /tmp/test.log

There is always more then one way.

[ericfjchen]

It works...
# tail -1 .profile | cut -d" " -f1