ksh script function extract line number

[Franky Leeuwerck_1]

Current status :
So far the proposals work for "Statistics" but not for "Statistics ( 2K)".

Franky

[Franky Leeuwerck_1]

Massimo,

I rememberd your earlier remark and had already tried this with the similar error :

syntax error The source line is 1.
The error context is
>>> /Statistics <<<
awk: Quitting
The source line is 1.

Franky

[Dagmar Boelen]

Hi Franky,

I got the same error on my workstation. The script work however worked fine!

#! /bin/ksh
function getLineNr {
# $1 search string
awk '/'$1'/{print NR}' myfile
}
TEST="Statistics ( 2K)"
ln=`getLineNr $TEST`

[Dagmar Boelen]

The error you mentioned only occurs when you parse a searchstring to the function which contains a space in it.

This means that a search for Statistics(2K) would work but that a search for Statistics (2K) would fail. The script I posted which uses parsing a $TEST instead of "Statistics (2K)" works however

[Franky Leeuwerck_1]

Dagmar

With your ' $TEST ' proposal, I can run the script without errors but it returns a wrong result.

I need line number. In the test it returns 3 line numbers, eg for the following lines :

! Statistics------------------------------------------------------------------
! Statistics ( 2K) -----------------------------------------------------------
! Statistics ( 4K) -----------------------------------------------------------

Franky

[Franky Leeuwerck_1]

For Massimo :

I combined your escaping remark with the $TEST remark from Dagmar.

$TEST="Statistics \( 2K\)"

The script runs without errors but with same wrong results.

Franky

[Massimo Bianchi]

Well,
and try to escape also the space :)

Massimo

[Massimo Bianchi]

Idea:


you get and error because the expansion lead to

getliner Statistics (2k)

and your function gets only the "statistics part.

Massimo

[Ian Lochray]

How about a different approach ...
#! /bin/ksh
getLineNr () {
# $1 search string
grep -n "$@" monitor_dmfcache.tmp | sed -e 's/:.*//'
}
ln=`getLineNr "Statistics ( 2K)"`
echo $ln

[Franky Leeuwerck_1]

Massimo,

Escaping also the second space give us the same (wrong) result.

Escaping the first space give us an error :

syntax error The source line is 1.
The error context is
/Statistics\/{ print >>> NR} <<<
awk: Quitting
The source line is 1.


Franky

[curt larson_1]

So far the proposals work for "Statistics" but not for "Statistics ( 2K)".

put double quotes around $1

awk '/'"$1"'/{print NR}' myfile

need line number. In the test it returns 3 line numbers

add a "-" to the end of your seach string, i.e. Statistics-

[curt larson_1]

also it would be better if you used

ln=$(getLineNR "Statistics ( 2K)")

instead of

ln=`getLineNr "Statistics ( 2K)"`

[Franky Leeuwerck_1]

Ian,

Nice try but got the following errors :
grep: can't open \(
grep: can't open 2K\)

Franky

[Dagmar Boelen]

Hi Franky,

This one outputs only one line (the correct one)!!!

#! /bin/ksh
function getLineNr {
# $1 search string
awk '/'$1'/{print NR}' myfile
}
TEST="Statistics/&&/(2K)"
ln=`getLineNr $TEST`

echo $ln

[Franky Leeuwerck_1]

Curt,

Your first remark did not gave other results.
The second one return in similar errors.

Thanks anyhow for helping me.

Franky

[Dagmar Boelen · Accepted solution]

Hi,

The script below is even better. It wil stop after it has printed the first line number where Statistics (2k) can be found. The previous would print 2 lines if Statistics (2K) occurs two time in the file which we analyze.

#! /bin/ksh
function getLineNr {
# $1 search string
awk '/'$1'/{print NR;exit 1}' myfile
}
TEST="Statistics/&&/(2K)"
ln=`getLineNr $TEST`

echo $ln
~

[Massimo Bianchi]

May be regular expression can help:

Modifying Ian's answer

#! /bin/ksh
getLineNr () {
# $1 search string

egrep -n "$1" monitor_dmfcache.tmp | awk -F: {print $1 }

}
ln=`getLineNr "Statistics.*2K"`
echo $ln


Massimo

[curt larson_1]

and your awk would probably be better if written like this

awk -v string="$1" '{
if ( $0 ~ string ) print NR;
}' yourFile

[Franky Leeuwerck_1]

Hello everyone,

I am trying out every one's proposals in FIFO and Dagmar has given me the solution that worked first.


Dagmar,
Good job.
can you explain to me the /&&/ stuff ?
I might need it for other strings.

To the other participants : thanks a many many many lot for your help. This was exciting.
I learned lot.

I will review the other suggestions also (and assign points if usefull).

Again thanks a lot.

Franky

[Dagmar Boelen]

/&&/ means match statistics and 2K. Unfortunatly this is not exactly what you want... It wil also match (2K) Statistics for example

[Franky Leeuwerck_1]

Ok Dagmar,

Thanks for the update.


Franky