lsof question

[KPS]

Hi

I have a need to use lsof to list open files for a specific user on my PA-RISC HP-UX 11.11 box.

I know if I use the fuser -u , that will show the open files that user has. Is there an option using lsof that gives you the actual amount of open files, because that's what I'm really after here.

Thanks,
KPS

[Coolmar · Accepted solution]

lsof -u username will list the open files by that user...so if you do the following:

# lsof -u username |wc -l

That will give you the number of files opened by a particular user. Is that what you were looking for?

[spex]

Hi,

I think you meant 'lsof -u '. How about:

# lsof -u user1 | wc -l
for a count of user1's open files, and

# lsof | wc -l
for a system-wide count?

PCS

[Sandman!]

lsof takes the same option as fuser...

# lsof -u

[Calandrello]

friend
lsof |grep process name

[KPS]

Thanks everyone, piping this to a wc -l is the way to go. Thanks!

[spex]

fuser(1M):
-u Display the login user name in parentheses following each
process ID.

lsof(8):
-u s This option selects the listing of files for the user whose
login names or user ID numbers are in the comma-separated set
s - e.g., ``abe'', or ``548,root''. (There should be no
spaces in the set.)

[Coolmar]

Hi again,

Would you be so kind as to assign points to any that helped you.
:0)