Precision "grep"

[D. Jackson_1]

I am trying to search an entire system for a specific ip address string (182.101.*). I DO NOT want the grep to pick up anything prior to the 182. . I am using this for my current search /> find ./ -type f -print |xargs grep "182.101." ...
Is there another way to get exactly what I need????
Thanks for the assistance...

[James R. Ferguson · Accepted solution]

Dustin:

Anchor the string, as:

...grep "^182"

...JRF...

[Stefan Farrelly]

I think your way of doing it is rather inefficient. It must build up a complete list from the find command before piping into xargs then into grep. I think its much faster and efficient to let find do the work;

find ./ -type f -exec grep "182.101." {} \;

[Rainer_1]

use grep "^182\.101\."
this pattern lists only lines the begins with 182

[D. Jackson_1]

Okay this worked both ways....
Thanks guys.

DJ

[D. Jackson_1]

Okay this worked both ways....
Thanks guys.

DJ