print fields in a row

[lawrenzo_1]

Hi all,

I am trying to print all occurances of a string that appear in a row so here is the file:

vpath12 12928727 = hdisk36 (Avail ) hdisk124 (Avail ) hdisk45 (Avail ) hdisk126 (Avail )
vpath23 40B28727 = hdisk42 (Avail ) hdisk136 (Avail ) hdisk59 (Avail ) hdisk138 (Avail )
vpath26 43128727 = hdisk50 (Avail ) hdisk70 (Avail ) hdisk143 (Avail ) hdisk149 (Avail )
vpath40 04D29942 = hdisk95 (Avail ) hdisk164 (Avail ) hdisk75 (Avail ) hdisk83 (Avail )


I would like the output to read

hdiskx hdiskx hdiskx hdiskx vpathx
and so on

thanks

[lawrenzo_1]

I suppose what I am tryingto achieve is that I want to use awk to check each field in the row and when the pattern is matched then it is printed:

awk '/vpath/ { vpath = $1};{for (i=1;i<=NF;++i)} {if ( i ~ hdisk ) {hdisk = i}} {print hdisk,vpath }'

16 vpath12
16 vpath23
16 vpath26
16 vpath40


not quite what I want ....

[James R. Ferguson · Accepted solution]

Hi Chris:

You're close:

# awk '/vpath/ {vpath=$1};{for (i=1;i<=NF;++i) {if ($i~/hdisk/) {PATH=PATH" "$i}};{print PATH,vpath}}' file

Regards!

...JRF...

[Peter Nikitka]

Hi,

try this:

awk '/^vpath/ {j=0; for(i=4;i
mfG Peter

[lawrenzo_1]

ok thanks guys - both work for me!

Chris.