[Q] shell programming - How to sum contents within list file using shell programming ?

[Tony, Lim]

I Occasionally might make list file only contain file size, like this.

# ls -l |awk '{print $5}' > list.txt

The result is like belows ..

2074654
11341023
11940435
558066
9160
10
201
1975
1894

What I want to do is to sum this contents as numbers to calculate total summation.

Could you let me know how to sum this contents using shell programming ??

[Senthil Kumar .A_1]

Hi tony,

Just do the following

ls -l|awk '{print $5}' | awk 'BEGIN {sum=0} {sum+=$1;print sum}'

You got ur solution.

Regards,
Senthil Kumar .A

[Senthil Kumar .A_1]

The last number in the output of the above command will be your Grand total(sum). You do not require to create a list.txt.

Even simpler is

ls -l | awk 'BEGIN {sum=0} {sum+=$5;print sum}'

This is even better..for u do not require 2 awk statements.

[Peter Godron]

Tony,
please note:
senthil's excellent solution appears to have a problem if sub-directories exist.

[Senthil Kumar .A_1]

Hi Tony,

I agree with peter,

U could use, command 'du -sk' instead for a disrectory.

If ur intension is just to sum up the fifth field, a much more elegent way is..

ls -l | awk 'BEGIN {sum=0} {sum+=$5} END {print sum}'

[Victor BERRIDGE]

Hi,
There many solutions for summation in shells, here Im using your list:
ant:/home/vbe $ tot_list
Total : 25927418 bytes
----
ant:/home/vbe $ more tot_list
count=0
for input in `cat list.txt`
do
count=`expr $count + $input`
done

print "Total : $count bytes \n"

---

All the best
Victor

[Muthukumar_5]

Use like,

ls -l | awk -v sum=0 '{ sum+=$5 } END { print sum; }'

--
Muthu

[Arturo Galbiati]

Hi,

using your command directly by awk:
ls -l | awk '{t+=$5};END {printf "%12d\n",t}'

More in general:
awk '{t+=$1};END {printf "%12d\n",t}' list.txt

where $1 is the field you want to summ

HTH,
Art

[Muthukumar_5]

If you want to know the disk usage of directory and sub level directories then simply use as,

# du -ks

It is returning KB size.

If you want to have the current directory files (without sub directory) then we can use,

# ls -l | awk -v sum=0 '{ sum+=$5; } END { print "Total Size in bytes are "sum }'

--
Muthu

[James R. Ferguson · Accepted solution]

Hi:

If all you want to count are the sizes of *files* in a simple 'ls' output, simply do:

# ls -l | awk '/^-/ {SUM+=$5};END{printf("%-12.0f\n",SUM)}'

If the first field doesn't begin with a "-" then it's not a regular file and we skip it.

Regards!

...JRF...