remove leading character

[John Roy Arendain]

Please advise what command do I use to remove the leading character "%" from the output of command "bdf â l | awk â {print $5}â "

[Michael Steele_2 · Accepted solution]

'^' for leading character.

Maybe:

# sed 's/^//g' filename

Try this handy SED URL:

http://www-h.eng.cam.ac.uk/help/tpl/unix/sed.html

[Bill Hassell]

Or you can use tr:

bdf | tr "%" " " | awk '{print $5}'

[Rajeev Shukla]

Use
bdf|awk '{print $5}'|sed 's/%//g'

[Rajeev Shukla]

And if you want %used to be left as it is try

bdf|awk '{print $5}'|sed 's/%$//g'

[John Roy Arendain]

Thanks Guys! our File system monitoring script is now complete. I am attaching the script file.

[Duncan Galbraith]

The bdf line in your script will only work for short filesystem names. Perhaps you are lucky and only have short names but on many systems the output of bdf for a filesystem often covers 2 lines so your bdf line might be better something like:
bdf ${FS[$i]} | grep " ${FS[$i]}$" | awk '{ print $(NF-1) }' | sed 's/%//'

[Graham Cameron_1]

And if you want to combine Duncan's fix to cope with > 1 line, and avoid grep and sed, doing it all with awk in one shot, how about.

bdf ${FS[$i]} |awk '/^Filesystem/ {next} (NF==1) {getline} {print substr($(NF-1),1,length($(NF-1)-1))}'

-- Graham