script to search more than 2 instances of same number in text file?

[Sammy_2]

(/bin/ksh or /bin/bash) shell
How to write script to print ONLY numbers which appear more than 2 times in a file below (numbers.txt).

So, output from from running thes scirpt (script.sh) after processing the txt file below should only show something like:
=================
#./script.sh

6 appears 3 times
1 appears 1 times

===================

numbers.txt
===========
12
12
111
111
6
6
6
1
22
22

[James R. Ferguson · Accepted solution]

Hi:

# uniq -c file

...which for your input yields:

2 12
2 111
3 6
1 1
2 22

Regards!

...JRF...

[Patrick Wallek]

If your file is not already sorted, you could do:

# sort -n numbers.txt | uniq -c

[Sammy_2]

JRF and Pat,
Thanks. It was simpler than I thougt. That is what I needed.
Appreciate it.
Sam

[Hein van den Heuvel]

Sammy, if you ever need more than counting. Maybe some pretty printing or further filtering the you may want to build on top of a perl/awk solution. Something like:

$ perl -ne 'chomp; $x{$_}++} { for (keys %x) {printf qq(%3d appears %3d times\n),$_,$x{$_}}' number.txt

22 appears 2 times
6 appears 3 times
1 appears 1 times
111 appears 2 times
12 appears 2 times

chomp; # take away new-line
$x{$_}++ # increment associative array element identified by line $_
} { # close input loop, open END block.
for (keys %x) { # what he said
printf qq(%3d appears %3d times\n) # formatted print
,$_,$x{$_} # variables are key and value for key
}' # close keys block, end program
number.txt # input stream.

hth,
Hein.