script

[Ana Perez_3]

Hello:

How can I eliminate the last character of a string in a shell script?

for example

pepitoA

to

pepito

Regards,
Mario.

[Sanjay Kumar Suri]

Use vi

:s/oldtext/newtext/g

sks

[Nicolas Dumeige · Accepted solution]

Hello Mario,

One way to do it :

#!/bin/ksh
var="012345"
length=${#var}
(( length -= 1 ))
echo $var | cut -c1-$length

cheers

[Mark Grant]

Or simply

expr "pepitoA" : "\(.*\)."

[Francisco J. Soler]

Hi Mario,

try this script:

STRING_A=pepitoA

STRING_B=`echo $STRING_A | awk '{printf("%s",substr($0,1,length($0)-1))}'`

echo $STRING_B

Be careful with the quotation.

Frank.

[Hoefnix]

Hi,
or use AWK.

echo pepitoA | awk '{ n=length($0)-1; print substr( $0, 0, n) }'

HTH,
Peter

[Nicolas Dumeige]

... or
# echo PepitoA | sed -e 's/.$//'
:)

[Steve Steel]

Hi

From shell man

${parameter%pattern}
${parameter%%pattern}
If the shell pattern matches the end of the
value of parameter, the value of parameter
with the matched part is deleted; otherwise
substitute the value of parameter. In the
former, the smallest matching pattern is
deleted; in the latter, the largest matching
pattern is deleted.


/home/steves >p=pepitoA
/home/steves >p=${p%?}
/home/steves >echo $p
pepito

Steve Steel

[Francisco J. Soler]

Hi Steve,

I think your answer is the best one. I take note of it.
Congratulations.

Frank.

[Shyjith P K]

Hi

You can use

sed 's/oldtext/netext/g' filename >filename

cheers
Shyjith

[Kiyoshi Miyake]

Hi.

The solusion of Steve is wonderful!

My solution :
printf "pepitoA" | perl -pe chop

(perl4 ok)